(2/3)^2x+11=(27/8)^x

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Solution for (2/3)^2x+11=(27/8)^x equation: 



(2/3)^2x+11=(27/8)^x

We move all terms to the left:

(2/3)^2x+11-((27/8)^x)=0



Domain of the equation: 3)^2x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 8)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)^2x-((+27/8)^x)+11=0

We calculate fractions


16^x)/3^2x*8)^x))+(-81^2x/3^2x*8)^x))+11=0

We can not solve this equation

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